Question

three elongated drops of blood were found on the floor in a room. the lengths of the drops were 4 mm, 10 mm, and 12 mm. the corresponding widths of each drop were 2 mm, 5 mm, and 6 mm. what was the angle of impact of each drop?
sin θ = \frac{w}{l}
angle θ sin θ
0
30 0.5
60 0.87
90 1
20°
30°
45°
90°

Explanation:

Step1: Calculate $\sin\theta$ for the first drop

Given $w = 2$ mm and $l=4$ mm, $\sin\theta_1=\frac{w}{l}=\frac{2}{4} = 0.5$

Step2: Find the angle for the first drop

From the table, when $\sin\theta = 0.5$, $\theta_1 = 30^{\circ}$

Step3: Calculate $\sin\theta$ for the second drop

Given $w = 5$ mm and $l = 10$ mm, $\sin\theta_2=\frac{w}{l}=\frac{5}{10}=0.5$

Step4: Find the angle for the second drop

From the table, when $\sin\theta = 0.5$, $\theta_2 = 30^{\circ}$

Step5: Calculate $\sin\theta$ for the third drop

Given $w = 6$ mm and $l = 12$ mm, $\sin\theta_3=\frac{w}{l}=\frac{6}{12}=0.5$

Step6: Find the angle for the third drop

From the table, when $\sin\theta = 0.5$, $\theta_3 = 30^{\circ}$

Answer:

$30^{\circ}$ for each drop.