Question

tions.notebook (x,y)→(x + 6,y + 2) l( , ) l( , ) m( , ) m( , ) n( , ) n( , ) o( , ) o( , )

Explanation:

Step1: Determine original coordinates

By observing the graph, we can see that \(L(- 5,1)\), \(M(-3,3)\), \(N(-3,4)\), \(O(-1,1)\)

Step2: Apply the translation rule \((x,y)\to(x + 6,y + 2)\) to point \(L\)

For \(L(-5,1)\), \(x=-5,y = 1\). Then \(x+6=-5 + 6=1\) and \(y + 2=1+2 = 3\). So \(L'(1,3)\)

Step3: Apply the translation rule \((x,y)\to(x + 6,y + 2)\) to point \(M\)

For \(M(-3,3)\), \(x=-3,y = 3\). Then \(x+6=-3+6 = 3\) and \(y + 2=3+2=5\). So \(M'(3,5)\)

Step4: Apply the translation rule \((x,y)\to(x + 6,y + 2)\) to point \(N\)

For \(N(-3,4)\), \(x=-3,y = 4\). Then \(x+6=-3 + 6=3\) and \(y + 2=4+2=6\). So \(N'(3,6)\)

Step5: Apply the translation rule \((x,y)\to(x + 6,y + 2)\) to point \(O\)

For \(O(-1,1)\), \(x=-1,y = 1\). Then \(x+6=-1+6 = 5\) and \(y + 2=1+2=3\). So \(O'(5,3)\)

Answer:

\(L(-5,1)\), \(L'(1,3)\)
\(M(-3,3)\), \(M'(3,5)\)
\(N(-3,4)\), \(N'(3,6)\)
\(O(-1,1)\), \(O'(5,3)\)