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the town mayor uses the graph to claim that the town is very pet friend…

Question

the town mayor uses the graph to claim that the town is very pet friendly. part a: find the mean of the data. show or explain each step of work. (2 points) part b: find the median of the data. show or explain each step of work. (1 point) part c: find the mode of the data. show or explain each step of work. (1 point) part d: using your findings in parts a, b, and c, describe the distribution of the data. (1 point)

Explanation:

Step1: Count the frequency of each value

Let's count the number of dots for each number of pets. For 0 pets, there is 1 dot; for 1 pet, 1 dot; for 2 pets, 2 dots; for 3 pets, 2 dots; for 4 pets, 4 dots; for 5 pets, 3 dots; for 6 pets, 2 dots; for 7 pets, 2 dots; for 8 pets, 2 dots; for 9 pets, 1 dot.

Step2: Calculate the sum of the products of values and their frequencies

The sum $S=(0\times1)+(1\times1)+(2\times2)+(3\times2)+(4\times4)+(5\times3)+(6\times2)+(7\times2)+(8\times2)+(9\times1)=0 + 1+4 + 6+16+15+12+14+16+9 =93$. The total number of data - points $n=1 + 1+2+2+4+3+2+2+2+1=20$.

Step3: Calculate the mean

The mean $\bar{x}=\frac{S}{n}=\frac{93}{20}=4.65$.

Step4: Find the median

Arrange the data in ascending order. Since $n = 20$ (an even - numbered data set), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+1)$th ordered data values. First, list out all the data values: 0, 1, 2, 2, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 6, 7, 7, 8, 8, 9. The 10th and 11th values are 4 and 5. So the median $M=\frac{4 + 5}{2}=4.5$.

Step5: Find the mode

The mode is the value that appears most frequently. The value 4 appears 4 times, more frequently than any other value, so the mode $Mo = 4$.

Step6: Describe the distribution

The mean ($4.65$), median ($4.5$) and mode ($4$) are relatively close. The distribution is approximately symmetric or slightly right - skewed since the mean is slightly larger than the median.

Answer:

Part A: The mean of the data is 4.65.
Part B: The median of the data is 4.5.
Part C: The mode of the data is 4.
Part D: The distribution is approximately symmetric or slightly right - skewed since the mean is slightly larger than the median, and the mean, median and mode are relatively close.