Question

a toy train locomotive pushes a wagon for 4 m with a force of 12 n. calculate the work done by the locomotive. make sure to draw the vectors force and displacement. givens: f = 12 n, s = 4 m. unknowns: what are you solving for? w. equation to use: w=. substitute & solve:

Explanation:

Step1: Recall work done formula

Work done is calculated as the product of force, displacement, and the cosine of the angle between them. Since the force and displacement are in the same direction, $\cos(0^\circ)=1$, so the formula simplifies to:
$$W = F \times s$$

Step2: Substitute given values

Plug in $F=12\ \text{N}$ and $s=4\ \text{m}$ into the formula:
$$W = 12\ \text{N} \times 4\ \text{m}$$

Step3: Calculate the result

Perform the multiplication to find work done:
$$W = 48\ \text{J}$$

Step4: Describe vector diagram

Draw a horizontal vector labeled $\vec{F} = 12\ \text{N}$ pointing to the right (direction of force). Draw a second horizontal vector of the same direction labeled $\vec{s} = 4\ \text{m}$ (displacement of the wagon).

Answer:

The work done by the locomotive is $\boldsymbol{48\ \text{J}}$.
Vector diagram: Two parallel, right-pointing vectors: one labeled $\vec{F}=12\ \text{N}$ (force from locomotive) and one labeled $\vec{s}=4\ \text{m}$ (displacement of the wagon).