Question

1. a train travels at a rate of 13 meters per second (m/s). over the next 60 seconds, the speed of the train increases to 22 m/s. what is the average rate of acceleration in m/s²?

Explanation:

Step1: Calcular cambio de velocidad

$\Delta v = v_f - v_i = 22 - 13 = 9 \, \text{m/s}$

Step2: Calcular aceleración promedio

$a = \frac{\Delta v}{\Delta t} = \frac{9}{60} = 0.15 \, \text{m/s}^2$

Answer:

0.15