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Question
transforming formulas
question
the formula to determine the period of one swing of a simple pendulum is $t = 2pisqrt{\frac{l}{g}}$, where $l$ is the length of the string and $g$ is the acceleration due to gravity. solve the formula to solve for $g$ in terms of $pi$, $t$ and $l$.
answer
attempt 1 out of 2
g =
submit answer
Step1: Square both sides
$T^{2}=(2\pi\sqrt{\frac{L}{g}})^2$
$T^{2}=4\pi^{2}\frac{L}{g}$
Step2: Cross - multiply
$T^{2}g = 4\pi^{2}L$
Step3: Solve for g
$g=\frac{4\pi^{2}L}{T^{2}}$
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$g=\frac{4\pi^{2}L}{T^{2}}$