Question

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1. treats the owner of a snow cone stand keeps track of the sizes and flavors sold one afternoon. he sold 100 snow cones in all. of these, 40 were large snow cones, 32 were grapes, and 12 were small watermelon snow cones. the stand sold 15 more cherry snow cones than grapes. the most popular snow cone of the day was small cherry, with a total of 35 sales.

a. construct a two - way frequency table to organize the data.
b. how many large grape snow cones were sold?
c. how many watermelon snow cones were sold in all?
d. how many more small snow cones were sold than large snow cones?

Explanation:

Step1: Calculate number of small snow - cones

Total snow - cones is 100 and large snow - cones is 40. So number of small snow - cones is $100 - 40=60$.

Step2: Calculate number of cherry snow - cones

Number of grape snow - cones is 32. Number of cherry snow - cones is $32 + 15=47$.

Step3: Fill in known values in the table

We know small watermelon is 12, small cherry is 35. So small grape is $60-(12 + 35)=13$. Large grape is $32 - 13 = 19$. Large watermelon is found by first finding total watermelon. Let total watermelon be $x$. Total cherry is 47, total grape is 32. So $x=100-(47 + 32)=21$. Then large watermelon is $21 - 12=9$. Large cherry is $47 - 35 = 12$.

	Small	Large	Total
Watermelon	12	9	21
Cherry	35	12	47
Total	60	40	100

Step4: Answer part b

Number of large grape snow - cones is 19.

Step5: Answer part c

Total watermelon snow - cones is 21.

Step6: Answer part d

Number of small snow - cones is 60 and large is 40. So $60-40 = 20$ more small snow - cones were sold than large snow - cones.

Answer:

b. 19
c. 21
d. 20