Question

this triangle is isosceles. find the value of x.\
(8x + 2)° (6x + 14)°\
x = ?

Explanation:

Step1: Recall Isosceles Triangle Property

In an isosceles triangle, the base angles (angles opposite the equal sides) are equal. So, we set the two angle expressions equal:
$8x + 2 = 6x + 14$

Step2: Solve for x

Subtract $6x$ from both sides:
$8x - 6x + 2 = 14$
$2x + 2 = 14$

Subtract 2 from both sides:
$2x = 14 - 2$
$2x = 12$

Divide both sides by 2:
$x = \frac{12}{2}$
$x = 6$

Answer:

$x = 6$