Question

triangle rst is reflected across the line y = -x. what are the coordinates of the resulting triangle? r(7, -2) s(-1, 2) t(0, 8) r(-2, 7) s(2, -1) t(8, 0) r(7, -2) s(-1, 2) t(0, 8) r(2, -7) s(-2, 1) t(0, -8) r(7, -2) s(-1, 2) t(0, 8) r(-7, 2) s(1, -2) t(0, -8) r(7, -2) s(-1, 2) t(0, 8) r(7, 2) s(-1, -2) t(0, 8)

Explanation:

Step1: Recall reflection rule

The rule for reflecting a point $(x,y)$ across the line $y=-x$ is $(x,y)\to(-y,-x)$.

Step2: Reflect point R

Given $R(8,-2)$, applying the rule: $x = 8,y=-2$, then $R'\to(2,-8)$.

Step3: Reflect point S

Given $S(-1,2)$, applying the rule: $x=-1,y = 2$, then $S'\to(2,-1)$.

Step4: Reflect point T

Given $T(0,8)$, applying the rule: $x = 0,y = 8$, then $T'\to(0,-8)$.

Answer:

R'(2, - 8), S'(2, - 1), T'(0, - 8)