QUESTION IMAGE
Question
triangles
independent practice
write and solve an equation to find the measures of each angle in the triangles shown below.
| triangle | equation and work | angle measures |
|---|---|---|
| 2. <img src=\triangle2.png\ alt=\triangle with vertices d, e, f. angle at d is (x + 20)°, angle at e is (3x)°, angle at f is 36°\> | _________________ | ∠d= ___<br>∠e= _<br>∠f= ___ |
| 3. <img src=\triangle3.png\ alt=\isosceles triangle with vertices g, h, i. angle at g is 28°, angle at h is x°, sides gh and gi are equal? wait, no, sides gh and hi? wait, the triangle has markings on gh and hi? wait, the image shows triangle ghi with angle at g 28°, and sides gh and hi marked as equal? wait, maybe its isosceles with gh = hi? so angles at g and i? wait, no, the angle at h is x°.> | _________________ | ∠g= ___<br>∠h= _<br>∠i= ___ |
| 4. <img src=\triangle4.png\ alt=\triangle with vertices j, k, l. angle at j is 41°, angle at k is (5x - 5)°, angle at l is (3x)°\> | _________________ | ∠j= ___<br>∠k= _<br>∠l= ___ |
- ∠m and ∠n are supplementary and ( mangle m = 37^circ ). if ( mangle n = (13x)^circ ), what is the value of ( x ) and the ( mangle n )?<br>\ta. equation: _______________<br>\tb. ( x = _ ), ( mangle m _ ), ( mangle n ___ )
- which angle pairs form complementary angles?<br><img src=\anglepairs.png\ alt=\angle diagram with point b, and rays ba, bd, be, bf, bc. angles: ba to bd is 25°, bd to be is 50°, be to bf is 65°, bf to bc is 40°.\>
Problem 1: Triangle ABC
Step1: Recall triangle angle sum (180°)
The sum of angles in a triangle is \( 180^\circ \). So, \( \angle A + \angle B + \angle C = 180^\circ \). Substituting the given angles: \( (2x + 8) + 63 + (x + 7) = 180 \).
Step2: Simplify and solve for \( x \)
Combine like terms: \( 2x + 8 + 63 + x + 7 = 180 \) → \( 3x + 78 = 180 \). Subtract 78: \( 3x = 102 \) → \( x = 34 \).
Step3: Find each angle
- \( \angle A = 2x + 8 = 2(34) + 8 = 76^\circ \)
- \( \angle B = 63^\circ \) (given)
- \( \angle C = x + 7 = 34 + 7 = 41^\circ \)
Step1: Triangle angle sum (180°)
\( \angle D + \angle E + \angle F = 180^\circ \). Substitute: \( (x + 20) + 3x + 36 = 180 \).
Step2: Solve for \( x \)
Combine terms: \( 4x + 56 = 180 \). Subtract 56: \( 4x = 124 \) → \( x = 31 \).
Step3: Calculate angles
- \( \angle D = x + 20 = 31 + 20 = 51^\circ \)
- \( \angle E = 3x = 3(31) = 93^\circ \)
- \( \angle F = 36^\circ \) (given)
Step1: Isosceles triangle (equal base angles)
Since \( GH = GI \), \( \angle H = \angle I = x^\circ \). Angle sum: \( 28 + x + x = 180 \).
Step2: Solve for \( x \)
\( 2x + 28 = 180 \) → \( 2x = 152 \) → \( x = 76 \).
Step3: Angles
- \( \angle G = 28^\circ \) (given)
- \( \angle H = 76^\circ \)
- \( \angle I = 76^\circ \)
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\( \angle A = 76^\circ \), \( \angle B = 63^\circ \), \( \angle C = 41^\circ \)