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Question
or trinomials (a=1)
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question
factor.
$x^2 - 3x - 10$
Step1: Find pair summing to -3, product -10
We need two numbers that add to $-3$ and multiply to $-10$. These numbers are $-5$ and $2$.
Step2: Split middle term and factor
Rewrite the trinomial using the pair, then factor by grouping:
$x^2 - 5x + 2x - 10 = x(x-5) + 2(x-5) = (x-5)(x+2)$
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$(x - 5)(x + 2)$