Question

1. trouver la largeur dun versant sachant que la course est de 23-9\ et lélévation est de 8-10\ (réponse en pieds-pouces, arrondir au pouces près). larg dun versant =

Explanation:

Step1: Convert all to inches

First, convert course and elevation to total inches:

• Course: $23'-9'' = (23 \times 12) + 9 = 276 + 9 = 285$ inches
• Elevation: $8'-10'' = (8 \times 12) + 10 = 96 + 10 = 106$ inches

Step2: Use Pythagorean theorem

The slope width is the hypotenuse of a right triangle with legs equal to course and elevation.
$$\text{Width} = \sqrt{\text{Course}^2 + \text{Elevation}^2}$$
$$\text{Width} = \sqrt{285^2 + 106^2}$$

Step3: Calculate squared values

$$285^2 = 81225, \quad 106^2 = 11236$$
$$\text{Sum} = 81225 + 11236 = 92461$$

Step4: Compute square root

$$\text{Width} = \sqrt{92461} \approx 304.07 \text{ inches}$$

Step5: Convert back to feet-inches

$$304.07 \div 12 = 25 \text{ feet remainder } 4.07 \text{ inches}$$
Round to nearest inch: 4 inches

Answer:

25'-4'' (or 304 inches)