Question

try this
board exam rating of bsed-ss graduates
(2021-2023) of jld university
89, 82, 75, 73, 74, 91, 80, 84, 88, 86,
75, 77, 79, 80, 84, 81, 83, 85, 90, 87,
76, 75, 74, 73, 93, 92, 87, 84, 86, 81,
85, 77, 73, 92, 91, 87, 85, 83, 77, 78,
80, 76, 77, 87, 88, 76, 90, 91, 81, 75

Explanation:

Since the problem isn't clearly stated (e.g., finding mean, median, mode, range, or something else about these scores), let's assume we want to find the mean (average) of the board exam ratings.

Step 1: Count the number of data points

First, we need to count how many scores there are. Let's list them and count:
89, 82, 75, 73, 74, 91, 80, 84, 88, 86,
75, 77, 79, 80, 84, 81, 83, 85, 90, 87,
76, 75, 74, 73, 93, 92, 87, 84, 86, 81,
85, 77, 73, 92, 91, 87, 85, 83, 77, 78,
80, 76, 77, 87, 88, 76, 90, 91, 81, 75

Let's count row by row:
Row 1: 10 scores
Row 2: 10 scores (total 20)
Row 3: 10 scores (total 30)
Row 4: 10 scores (total 40)
Row 5: 10 scores (total 50)
So there are \( n = 50 \) data points.

Step 2: Sum all the scores

Now we sum all the scores. Let's add them step by step:

First, list the scores and add:

89 + 82 = 171
171 + 75 = 246
246 + 73 = 319
319 + 74 = 393
393 + 91 = 484
484 + 80 = 564
564 + 84 = 648
648 + 88 = 736
736 + 86 = 822

Row 1 total: 822

Row 2: 75 + 77 = 152
152 + 79 = 231
231 + 80 = 311
311 + 84 = 395
395 + 81 = 476
476 + 83 = 559
559 + 85 = 644
644 + 90 = 734
734 + 87 = 821

Row 2 total: 821

Row 3: 76 + 75 = 151
151 + 74 = 225
225 + 73 = 298
298 + 93 = 391
391 + 92 = 483
483 + 87 = 570
570 + 84 = 654
654 + 86 = 740
740 + 81 = 821

Row 3 total: 821

Row 4: 85 + 77 = 162
162 + 73 = 235
235 + 92 = 327
327 + 91 = 418
418 + 87 = 505
505 + 85 = 590
590 + 83 = 673
673 + 77 = 750
750 + 78 = 828

Row 4 total: 828

Row 5: 80 + 76 = 156
156 + 77 = 233
233 + 87 = 320
320 + 88 = 408
408 + 76 = 484
484 + 90 = 574
574 + 91 = 665
665 + 81 = 746
746 + 75 = 821

Row 5 total: 821

Now sum all row totals: 822 + 821 + 821 + 828 + 821
822 + 821 = 1643
1643 + 821 = 2464
2464 + 828 = 3292
3292 + 821 = 4113

So the total sum \( \sum x = 4113 \)

Step 3: Calculate the mean

The formula for the mean \( \bar{x} \) is \( \bar{x} = \frac{\sum x}{n} \)

We have \( \sum x = 4113 \) and \( n = 50 \)

So \( \bar{x} = \frac{4113}{50} = 82.26 \)

Answer:

If we were finding the mean, the answer is \( 82.26 \). If the problem was different (e.g., median, mode), the approach would change. Since the problem wasn't specified, assuming mean, the average board exam rating is \( 82.26 \).