Question

try solving $x^2 - 6x + 2 = 0$ by using the quadratic equation.
solve $x^2 - 6x + 2 = 0$ using the quadratic equation. if you have a square root that does not simplify as a whole number evenly, round to the nearest tenth (1 decimal place).
write your answer as x=, x= (for example: x=2, x=-3).

Explanation:

Step1: Identify quadratic coefficients

For $ax^2+bx+c=0$, $a=1$, $b=-6$, $c=2$

Step2: Recall quadratic formula

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

Step3: Calculate discriminant

$\Delta = (-6)^2-4(1)(2)=36-8=28$

Step4: Substitute into formula

$$x=\frac{6\pm\sqrt{28}}{2}=\frac{6\pm2\sqrt{7}}{2}=3\pm\sqrt{7}$$

Step5: Compute decimal values

$\sqrt{7}\approx2.6458$, so $3+2.6458\approx5.6$, $3-2.6458\approx0.4$

Answer:

$x \approx 5.6$, $x \approx 0.4$