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Question
try these on your own.
- $(4^{2})^{-1} =$
- $(3^{3})^{-2} =$
- $sqrt{2^{-4}} =$
- $sqrt3{3^{-3}} =$
- $sqrt{(4^{-2})^{3}} =$
- $x^{-1}y^{2}z^{-3} =$
- $(z^{3})^{-2} =$
- $4^{-5} =$
- $x^{-6} =$
- $2x^{-2} =$
- $\frac{2^{15}}{2^{18}} =$
- $\frac{6^{2}}{6^{3}} =$
- $4^{2} \div 4^{5} =$
- $\frac{6^{3}}{6^{5}} =$
- $\frac{8^{2}}{8^{4}} =$
- $\frac{0.2^{3}}{0.2^{5}} =$
- $(x^{3}y^{2}z) \div (x^{4}y^{3}z^{2}) =$
- $\frac{4^{4}a^{2}b^{3}c}{4^{5}a^{2}b^{3}c} =$
- $\frac{def}{d^{2}ef^{3}} =$
- $\frac{x^{2}y^{3}z}{x^{6}y^{5}z^{5}} =$
Step1: Apply exponent rule $(a^m)^n=a^{mn}$
- $(4^2)^{-1}=4^{2\times(-1)}=4^{-2}=\frac{1}{4^2}=\frac{1}{16}$
- $(3^3)^{-2}=3^{3\times(-2)}=3^{-6}=\frac{1}{3^6}=\frac{1}{729}$
- $(z^3)^{-2}=z^{3\times(-2)}=z^{-6}=\frac{1}{z^6}$
Step2: Convert roots to exponents $\sqrt[n]{a}=a^{\frac{1}{n}}$
- $\sqrt{2^{-4}}=(2^{-4})^{\frac{1}{2}}=2^{-4\times\frac{1}{2}}=2^{-2}=\frac{1}{4}$
- $\sqrt[3]{3^{-3}}=(3^{-3})^{\frac{1}{3}}=3^{-3\times\frac{1}{3}}=3^{-1}=\frac{1}{3}$
- $\sqrt{(4^{-2})^3}=((4^{-2})^3)^{\frac{1}{2}}=4^{-2\times3\times\frac{1}{2}}=4^{-3}=\frac{1}{64}$
Step3: Rewrite negative exponents $a^{-n}=\frac{1}{a^n}$
- $x^{-1}y^2z^{-3}=\frac{y^2}{x z^3}$
- $4^{-5}=\frac{1}{4^5}=\frac{1}{1024}$
- $x^{-6}=\frac{1}{x^6}$
- $2x^{-2}=\frac{2}{x^2}$
Step4: Apply quotient rule $\frac{a^m}{a^n}=a^{m-n}$
- $\frac{2^{15}}{2^{18}}=2^{15-18}=2^{-3}=\frac{1}{8}$
- $\frac{6^2}{6^3}=6^{2-3}=6^{-1}=\frac{1}{6}$
- $4^2\div4^5=4^{2-5}=4^{-3}=\frac{1}{64}$
- $\frac{6^3}{6^5}=6^{3-5}=6^{-2}=\frac{1}{36}$
- $\frac{8^2}{8^4}=8^{2-4}=8^{-2}=\frac{1}{64}$
- $\frac{0.2^3}{0.2^5}=0.2^{3-5}=0.2^{-2}=\frac{1}{0.2^2}=25$
Step5: Apply quotient rule to variables
- $(x^3y^2z)\div(x^4y^3z^2)=x^{3-4}y^{2-3}z^{1-2}=x^{-1}y^{-1}z^{-1}=\frac{1}{xyz}$
- $\frac{4^4a^2b^3c}{4^5a^2b^3c}=4^{4-5}a^{2-2}b^{3-3}c^{1-1}=4^{-1}=\frac{1}{4}$
- $\frac{def}{d^2e^3f^3}=d^{1-2}e^{1-3}f^{1-3}=d^{-1}e^{-2}f^{-2}=\frac{1}{d e^2 f^2}$
- $\frac{x^2y^3z}{x^6y^5z^5}=x^{2-6}y^{3-5}z^{1-5}=x^{-4}y^{-2}z^{-4}=\frac{1}{x^4 y^2 z^4}$
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