Question

1. in a tug of war, 5 donkeys are exactly equal to 2 elephants. in another tug of war, 3 elephants are equal to 1 car. which team should win if a car and 3 donkeys are matched against 4 elephants?

answer:

Explanation:

Step1: Define variables

Let \( d \) represent donkeys, \( e \) represent elephants, and \( c \) represent cars. We know \( 5d = 2e \) and \( 3e = c \).

Step2: Express car in terms of donkeys

From \( 3e = c \), we can express \( e=\frac{c}{3} \). Substitute into \( 5d = 2e \):
\( 5d = 2\times\frac{c}{3} \), so \( c=\frac{15d}{2}=7.5d \).

Step3: Calculate total for car + 3 donkeys

The team with a car and 3 donkeys has a total of \( c + 3d = 7.5d+3d = 10.5d \).

Step4: Express 4 elephants in terms of donkeys

From \( 5d = 2e \), we get \( e=\frac{5d}{2} \). So \( 4e = 4\times\frac{5d}{2}=10d \).

Step5: Compare the two teams

Since \( 10.5d>10d \), the team with a car and 3 donkeys is stronger.

Answer:

The team with a car and 3 donkeys should win.