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Question
if ∠tuv and ∠pqr are a linear pair, and m∠tuv is equal to 88°, then what is m∠pqr? m∠pqr = ?°
Step1: Recall linear - pair property
The sum of angles in a linear pair is 180°. So, \(m\angle TUV + m\angle PQR=180^{\circ}\).
Step2: Solve for \(m\angle PQR\)
We know \(m\angle TUV = 88^{\circ}\). Then \(m\angle PQR=180^{\circ}-m\angle TUV\). Substitute \(m\angle TUV = 88^{\circ}\) into the equation: \(m\angle PQR = 180 - 88\).
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