Question

a twelve - sided die with sides labeled 1 through 12 will be rolled once. each number is equally likely to be rolled. what is the probability of rolling a number greater than 10? write your answer as a fraction in simplest form.

Explanation:

Step1: Count total outcomes

Total sides = 12, so total outcomes = 12.

Step2: Count favorable outcomes

Numbers >10: 11,12 → 2 outcomes.

Step3: Calculate probability

Probability = $\frac{\text{favorable}}{\text{total}} = \frac{2}{12}$

Step4: Simplify fraction

Divide numerator/denominator by 2: $\frac{1}{6}$

Answer:

$\frac{1}{6}$