Question

two right triangles, $\triangle abd$ and $\triangle acd$, were created from $\triangle abc$ by constructing $\overline{ad} \perp \overline{cb}$.
follow these steps to prove that $\frac{\sin(b)}{b} = \frac{\sin(c)}{c}$.

1. for $\triangle abd, \sin(b) = $
2. multiply both sides of the equation by $c$ and simplify. the equation $\sin(b) = \frac{h}{c}$ becomes

Explanation:

Step1: Multiply both sides by $c$

$\sin(B) \times c = \frac{h}{c} \times c$

Step2: Simplify the right-hand side

$\sin(B) \times c = h$

Answer:

$c\sin(B) = h$