Question

1. two spinners are shown below. if both spinners are spun at the same time, what is the probability of spinning a b on both spinners?

a (\frac{1}{12})
b (\frac{1}{6})
c (\frac{11}{12})
d (\frac{7}{12})
spinner 1 (top) is a circle divided into four equal sections labeled a, b, c, d. spinner 2 (bottom) is a circle divided into three sections: one labeled a, two labeled b.

Explanation:

Step1: Find probability of B on Spinner 1

Spinner 1 has 4 equal sections, 1 is B. So probability is $\frac{1}{4}$.

Step2: Find probability of B on Spinner 2

Spinner 2 has 3 sections, 2 are B. So probability is $\frac{2}{3}$.

Step3: Multiply the two probabilities

To find the probability of both events (B on Spinner 1 and B on Spinner 2) happening, multiply the probabilities: $\frac{1}{4} \times \frac{2}{3} = \frac{2}{12} = \frac{1}{6}$.

Answer:

B. $\frac{1}{6}$