Question

the two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.

	4-wheel drive	no 4-wheel drive	total
no third-row seats	7	28	35
total	25	40	65

what is the probability that a randomly selected car with no 4-wheel drive has third-row seats?
\\(\circ\\) 0.3
\\(\circ\\) 0.4
\\(\circ\\) 0.7
\\(\circ\\) 0.8

Explanation:

Step1: Identify relevant values

We need the number of cars with no 4-wheel drive AND third-row seats (12) and the total number of cars with no 4-wheel drive (40).

Step2: Calculate conditional probability

Divide the favorable count by the total count of the subset.
$\text{Probability} = \frac{12}{40}$

Step3: Simplify the fraction

$\frac{12}{40} = 0.3$

Answer:

0.3