Question

b) un balloon a un volume de 75 l à 25 °c. de combien doit - on augmenter la température pour obtenir un balloon dont le volume sera de 100 l à la même pression ?

Explanation:

Step1: Convert Celsius to Kelvin

$T_1 = 25 + 273.15=298.15\ K$

Step2: Apply Charles's Law ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$)

$T_2=\frac{V_2T_1}{V_1}$
Substitute $V_1 = 75\ L$, $T_1 = 298.15\ K$, $V_2 = 100\ L$ into the formula.
$T_2=\frac{100\times298.15}{75}\approx397.53\ K$

Step3: Calculate the temperature increase

$\Delta T=T_2 - T_1$
$\Delta T=397.53 - 298.15 = 99.38\ K$
In Celsius, the increase is also $99.38^{\circ}C$ (since a change of 1 K is equal to a change of 1°C).

Answer:

$99.38^{\circ}C$