Question

une solution de sulfate de cuivre (cuso₄) a une concentration de 1,2 mol/l. vous avez 0,6 mole de cuso₄. quel volume de solution contient cette quantité de cuso₄ ? 2 points
a 1,5 mol
b 1 mol
c 0,25 mol
d 2 mol
e 0,5 mol

Explanation:

Step1: Recall the formula for molarity

The formula for molarity \( M \) is \( M=\frac{n}{V} \), where \( n \) is the number of moles and \( V \) is the volume in liters. We need to solve for \( V \), so we can rearrange the formula to \( V = \frac{n}{M} \).

Step2: Substitute the given values

We are given that \( n = 0.6 \) moles and \( M=1.2 \) mol/L. Substituting these values into the formula \( V=\frac{n}{M} \), we get \( V=\frac{0.6\space mol}{1.2\space mol/L} \).

Step3: Calculate the volume

Calculating \( \frac{0.6}{1.2} \), we get \( 0.5 \) L. Wait, but the options are in moles? Wait, no, maybe there is a mistake in the options or maybe I misread. Wait, the question is about volume, but the options are in moles. Wait, maybe the question was mistyped, but if we assume that maybe it's a miscalculation or maybe the question is about moles in a different way? Wait, no, let's re - check. Wait, the formula for molarity is \( M=\frac{n}{V} \), so \( V=\frac{n}{M}=\frac{0.6}{1.2} = 0.5\space L \), but the options are in moles. Wait, maybe the question is actually asking for something else, but among the options, E is 0.5 mol. Maybe there was a mistake in the question, but based on the calculation of \( \frac{0.6}{1.2}=0.5 \), the answer should be E.

Answer:

E. 0,5 mol