Question

unit fractions and mixed numbers
progress:
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answers.
which of the following shows \\(\frac{18}{12}\\) as a mixed number and \\(1\frac{7}{8}\\) as an improper fraction?
\\(\frac{18}{12} = 1\frac{1}{2}\\) and \\(1\frac{7}{8} = \frac{15}{8}\\)
\\(\frac{18}{12} = 1\frac{6}{12}\\) and \\(1\frac{7}{8} = \frac{8}{8}\\)
\\(\frac{18}{12} = \frac{9}{6}\\) and \\(1\frac{7}{8} = 1\frac{8}{7}\\)
\\(\frac{18}{12} = \frac{3}{2}\\) and \\(1\frac{7}{8} = \frac{17}{8}\\)

Explanation:

Step1: Convert $\frac{18}{12}$ to mixed number

Divide 18 by 12: $18\div12=1$ with remainder 6. So $\frac{18}{12}=1\frac{6}{12}$, simplify the fraction part: $\frac{6}{12}=\frac{1}{2}$, so $\frac{18}{12}=1\frac{1}{2}$.

Step2: Convert $1\frac{7}{8}$ to improper fraction

Use the formula: $a\frac{b}{c}=\frac{a\times c + b}{c}$. Substitute $a=1, b=7, c=8$: $\frac{1\times8 + 7}{8}=\frac{15}{8}$.

Answer:

A. $\frac{18}{12}=1\frac{1}{2}$ and $1\frac{7}{8}=\frac{15}{8}$