Question

q. from your unit 1 review notes: in a class of 30 students, there are 17 girls and 13 boys. five are a students, and three of these students are girls. if a student is chosen at random, what is the probability of choosing a girl or an a student?

Explanation:

Step1: Define given values

Total students $n(T)=30$, Girls $n(G)=17$, A students $n(A)=5$, Girl A students $n(G\cap A)=3$

Step2: Apply addition rule

Probability formula: $P(G\cup A)=P(G)+P(A)-P(G\cap A)$
Substitute values: $P(G\cup A)=\frac{17}{30}+\frac{5}{30}-\frac{3}{30}$

Step3: Calculate final probability

Simplify the expression: $\frac{17+5-3}{30}=\frac{19}{30}$

Answer:

$\frac{19}{30}$