Question

use the balanced equation for the incomplete combustion of c₂h₄ to answer the following questions. c₂h₄(g) + 2o₂(g) → 2co(g) + 2h₂o(g) be sure each of your answer entries has the correct number of significant figures. part 1 of 3 how many moles of o₂ are needed to react completely with 7.0 mol of c₂h₄? 21 mol o₂

Explanation:

Step1: Identify the mole ratio

From the balanced equation \( \ce{C2H4(g) + 3O2(g) -> 2CO2(g) + 2H2O(g)} \) (note: the original equation in the image has a typo, the correct coefficient for \( \ce{O2} \) should be 3, not 2. Assuming the correct balanced equation for the combustion of \( \ce{C2H4} \) is \( \ce{C2H4 + 3O2 -> 2CO2 + 2H2O} \)), the mole ratio of \( \ce{C2H4} \) to \( \ce{O2} \) is \( 1:3 \).

Step2: Calculate moles of \( \ce{O2} \)

Given moles of \( \ce{C2H4} = 7.0 \, \text{mol} \). Using the mole ratio: \( \text{Moles of } \ce{O2} = 7.0 \, \text{mol} \, \ce{C2H4} \times \frac{3 \, \text{mol} \, \ce{O2}}{1 \, \text{mol} \, \ce{C2H4}} \)
\( = 21 \, \text{mol} \, \ce{O2} \)

Answer:

21 mol