Question

use the diagram above to answer the next question. some blood was withdrawn from a persons arm. the blood was then placed in a beaker with some salt solution. when the red blood cells in this solution were then viewed under the microscope. the results are shown in the diagram above. in which of the following solutions was the red blood cells placed? select one: a. 0.009% solution of sodium chloride b. 0.09% solution of sodium chloride c. 9% solution of sodium chloride d. 0.9% solution of sodium chloride

Explanation:

The red - blood cell in the diagram is crenated (shriveled), which indicates it is in a hypertonic solution. A hypertonic solution has a higher solute concentration than the cell's interior. Normal saline (isotonic to blood cells) is 0.9% sodium chloride. A 9% sodium chloride solution is hypertonic compared to the red - blood cell's internal environment, causing water to leave the cell and resulting in crenation.

Answer:

C. 9% solution of sodium chloride