Question

use the drop - down menus to complete the statements. therefore, △jkl is 4² is 3²+3². 5² is 3²+4². applying the same method, △abc is

Explanation:

Step1: Recall the Pythagorean theorem

For a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse. In \(\triangle ABC\), \(3^{2}+4^{2}=9 + 16=25=5^{2}\), so \(\triangle ABC\) is a right - triangle.

Step2: Check \(\triangle JKL\)

In \(\triangle JKL\), \(3^{2}+3^{2}=9 + 9 = 18\), and \(4^{2}=16\). Since \(3^{2}+3^{2}
eq4^{2}\), \(\triangle JKL\) is not a right - triangle.

Answer:

Therefore, \(\triangle JKL\) is not a right - triangle. Applying the same method, \(\triangle ABC\) is a right - triangle.