QUESTION IMAGE
Question
use the following table to answer the question.
| strong acids | weak acids | weak bases | strong bases |
|---|---|---|---|
| hcl | hf | nh₄oh | koh |
| h₂so₄ | hcn | cu(oh)₂ | ca(oh)₂ |
which reaction yields a salt with the highest ph?
- ( \boldsymbol{koh + h_2so_4} )
- ( \boldsymbol{cu(oh)_2 + h_2so_4} )
- ( \boldsymbol{nh_4oh + hcl} )
- ( \boldsymbol{naoh + ch_3cooh} )
Brief Explanations
- Recall the nature of salts formed from acid - base reactions:
- For a reaction between a strong acid (\( SA \)) and a strong base (\( SB \)): The salt formed is neutral, so \( pH = 7 \). For example, in the reaction \( KOH(\text{strong base})+H_2SO_4(\text{strong acid})\), the salt \( K_2SO_4 \) is neutral.
- For a reaction between a strong acid (\( SA \)) and a weak base (\( WB \)): The salt formed is acidic, so \( pH<7 \). For example, in the reaction \( NH_4OH(\text{weak base}) + HCl(\text{strong acid})\), the salt \( NH_4Cl \) is acidic.
- For a reaction between a weak acid (\( WA \)) and a strong base (\( SB \)): The salt formed is basic, so \( pH > 7 \).
- For a reaction between a weak acid (\( WA \)) and a weak base (\( WB \)): The \( pH \) of the salt depends on the relative strengths of the acid and base. For example, in the reaction \( Cu(OH)_2(\text{weak base})+H_2SO_4(\text{strong acid})\), the salt \( CuSO_4 \) is acidic (since strong acid and weak base react).
- Analyze each option:
- Option 1: \( KOH + H_2SO_4 \): \( KOH \) is a strong base, \( H_2SO_4 \) is a strong acid. The salt \( K_2SO_4 \) is neutral (\( pH = 7 \)).
- Option 2: \( Cu(OH)_2+H_2SO_4 \): \( Cu(OH)_2 \) is a weak base, \( H_2SO_4 \) is a strong acid. The salt \( CuSO_4 \) is acidic (\( pH<7 \)).
- Option 3: \( NH_4OH + HCl \): \( NH_4OH \) is a weak base, \( HCl \) is a strong acid. The salt \( NH_4Cl \) is acidic (\( pH<7 \)).
- Option 4: \( NaOH+CH_3COOH \): \( NaOH \) is a strong base, \( CH_3COOH \) is a weak acid. The salt \( CH_3COONa \) is basic (\( pH > 7 \)). Among the options, the salt formed from a weak acid and a strong base will have the highest \( pH \) (since basic salts have \( pH>7 \) and acidic/neutral salts have \( pH\leq7 \)). So the reaction \( NaOH + CH_3COOH \) yields a salt with the highest \( pH \).
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D. \( NaOH + CH_3COOH \)