QUESTION IMAGE
Question
use the number line to find the coordinate of the midpoint of each segment.
e f g h j k l
-6 -4 -2 0 2 4 6 8 10
- (overline{fk}) 8. (overline{hk}) 9. (overline{ef})
- (overline{fg}) 11. (overline{jl}) 12. (overline{el})
use tools use the number line to find the coordinate of the midpoint of each segment.
a b c d e
-6 -4 -2 0 2 4 6 8 10 12
- (overline{de}) 14. (overline{bc})
- (overline{bd}) 16. (overline{ad})
Step1: Recall mid - point formula on number line
The mid - point of a line segment with endpoints $x_1$ and $x_2$ on a number line is given by $\frac{x_1 + x_2}{2}$.
Step2: Solve for $\overline{FK}$
The coordinate of $F=-2$ and the coordinate of $K = 9$. So the mid - point is $\frac{-2 + 9}{2}=\frac{7}{2}=3.5$.
Step3: Solve for $\overline{HK}$
The coordinate of $H = 3$ and the coordinate of $K = 9$. So the mid - point is $\frac{3+9}{2}=\frac{12}{2}=6$.
Step4: Solve for $\overline{EF}$
The coordinate of $E=-6$ and the coordinate of $F=-2$. So the mid - point is $\frac{-6+( - 2)}{2}=\frac{-8}{2}=-4$.
Step5: Solve for $\overline{FG}$
The coordinate of $F=-2$ and the coordinate of $G = 0$. So the mid - point is $\frac{-2 + 0}{2}=-1$.
Step6: Solve for $\overline{JL}$
The coordinate of $J = 6$ and the coordinate of $L = 10$. So the mid - point is $\frac{6 + 10}{2}=\frac{16}{2}=8$.
Step7: Solve for $\overline{EL}$
The coordinate of $E=-6$ and the coordinate of $L = 10$. So the mid - point is $\frac{-6+10}{2}=\frac{4}{2}=2$.
Step8: Solve for $\overline{DE}$
The coordinate of $D = 6$ and the coordinate of $E = 10$. So the mid - point is $\frac{6 + 10}{2}=8$.
Step9: Solve for $\overline{BC}$
The coordinate of $B=-2$ and the coordinate of $C = 2$. So the mid - point is $\frac{-2 + 2}{2}=0$.
Step10: Solve for $\overline{BD}$
The coordinate of $B=-2$ and the coordinate of $D = 6$. So the mid - point is $\frac{-2+6}{2}=\frac{4}{2}=2$.
Step11: Solve for $\overline{AD}$
The coordinate of $A=-4$ and the coordinate of $D = 6$. So the mid - point is $\frac{-4 + 6}{2}=\frac{2}{2}=1$.
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