Question

use the periodic table in the tools bar to complete the electron configurations for the following elements: lithium (li): 1s^a2s^b a = 2 b = 1 complete beryllium (be): 1s^c2s^d c = 2 d = 2 complete boron (b): 1s^e2s^f2p^g e = f = g = done

Explanation:

Step1: Recall electron - filling rules

Electrons fill orbitals in order of increasing energy. The 1s orbital fills first, holding a maximum of 2 electrons. Then the 2s orbital fills, also holding a maximum of 2 electrons, and then the 2p orbitals start to fill.

Step2: Determine electron configuration for boron

Boron has an atomic number of 5, meaning it has 5 electrons. The first 2 electrons go in the 1s orbital, so $E = 2$. The next 2 electrons go in the 2s orbital, so $F = 2$. The remaining 1 electron goes in the 2p orbital, so $G = 1$.

Answer:

$E = 2$
$F = 2$
$G = 1$