QUESTION IMAGE
Question
2 use the pythagorean theorem to find the distance between (3, 0) and (7, -6). round to the nearest tenth
Step1: Find the horizontal and vertical distances
The horizontal distance $x$ between the points $(3,0)$ and $(7, - 6)$ is the difference in $x$-coordinates: $x=\vert7 - 3\vert=4$. The vertical distance $y$ is the difference in $y$-coordinates: $y=\vert-6 - 0\vert = 6$.
Step2: Apply the Pythagorean Theorem
The Pythagorean Theorem for the distance $d$ between two points is $d=\sqrt{x^{2}+y^{2}}$. Substitute $x = 4$ and $y = 6$ into the formula: $d=\sqrt{4^{2}+6^{2}}=\sqrt{16 + 36}=\sqrt{52}$.
Step3: Simplify and round
$\sqrt{52}\approx7.2$.
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$7.2$