Question

use the quadratic formula to solve. express your answer in simplest form. 3x² + 20x + 25 = 0 answer attempt 1 out of 2 additional solution no solution x =

Explanation:

Step1: Identify coefficients

For the quadratic equation $3x^{2}+20x + 25=0$, $a = 3$, $b = 20$, $c = 25$.

Step2: Calculate the discriminant

The discriminant $\Delta=b^{2}-4ac=(20)^{2}-4\times3\times25=400 - 300=100$.

Step3: Apply the quadratic formula

The quadratic formula is $x=\frac{-b\pm\sqrt{\Delta}}{2a}$. Substitute the values: $x=\frac{-20\pm\sqrt{100}}{2\times3}=\frac{-20\pm10}{6}$.

Step4: Find the two solutions

For the plus - sign: $x_1=\frac{-20 + 10}{6}=\frac{-10}{6}=-\frac{5}{3}$.
For the minus - sign: $x_2=\frac{-20-10}{6}=\frac{-30}{6}=- 5$.

Answer:

$x = - 5,-\frac{5}{3}$