Question

use substitution to solve the system.\\(x - 3y = -10\\)\\(5x - 3y = -14\\)\\(x = \square\\)\\(y = \square\\)

Explanation:

Step1: Isolate $x$ from first equation

$x = 3y - 10$

Step2: Substitute $x$ into second equation

$5(3y - 10) - 3y = -14$

Step3: Simplify and solve for $y$

$15y - 50 - 3y = -14$
$12y = 36$
$y = 3$

Step4: Substitute $y$ back to find $x$

$x = 3(3) - 10 = 9 - 10$
$x = -1$

Answer:

$x = -1$
$y = 3$