Question

use the table to answer the following question: given the dominant gene for the left thumb, what is the theoretical probability that a child will naturally place the left thumb on top, if the father has gene pair gg and the mother has gg? (the table is a punnett square with gene from mother (g, g, gg) and gene from father (g, gg, gg))

Explanation:

Step1: Identify dominant genotypes

A child will have the trait if they have at least one dominant gene $G$, so genotypes $Gg$ or $GG$.

Step2: Count favorable outcomes

From the Punnett square, the favorable genotypes are $Gg$ (2 instances). Total possible outcomes are 4.

Step3: Calculate probability

$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{2}{4} = 0.5 = 50\%$

Answer:

50%