Question

1. using the law of conservation of mass, determine the missing mass values.

hcl + naoh → nacl + h₂o
mass 50g + 65g → 100g + ____

Explanation:

Step1: Recall Law of Conservation of Mass

The law states that the total mass of reactants equals the total mass of products. So, mass of \( \text{HCl} + \text{NaOH} = \text{mass of } \text{NaCl} + \text{H}_2\text{O} \).

Step2: Calculate Total Mass of Reactants

Mass of \( \text{HCl} = 50 \, \text{g} \), mass of \( \text{NaOH} = 65 \, \text{g} \). Total reactant mass: \( 50 + 65 = 115 \, \text{g} \).

Step3: Let Missing Mass be \( x \) (mass of \( \text{H}_2\text{O} \))

Total product mass: \( 100 + x \). By conservation of mass: \( 115 = 100 + x \).

Step4: Solve for \( x \)

Subtract 100 from both sides: \( x = 115 - 100 = 15 \, \text{g} \).

Answer:

The missing mass is \( 15 \, \text{g} \).