Question

using the vsepr model, predict the electron domain geometry and the molecular geometry of each species (bent, linear, octahedral, seesaw, square planar, square pyramidal, t - shaped, tetrahedral, trigonal bipyramidal, trigonal planar, or trigonal pyramidal).
part 1 of 4
nbr₃
electron domain geometry: select
molecular geometry: select
part 2 of 4
xeo₄
electron domain geometry: select
molecular geometry: select

Explanation:

Step1: Determine valence - electron pairs for NBr₃

N has 5 valence electrons and each Br contributes 7 valence electrons. NBr₃ has 5 + 3×7=26 valence electrons. The central N atom has 3 bonding pairs (with Br atoms) and 1 lone - pair. The total number of electron domains around N is 4 (3 bonding + 1 non - bonding). According to VSEPR, the electron - domain geometry for 4 electron domains is tetrahedral.

Step2: Determine molecular geometry of NBr₃

With 3 bonding pairs and 1 lone - pair around the central N atom, the molecular geometry is trigonal pyramidal due to the repulsion of the lone - pair.

Step3: Determine valence - electron pairs for XeO₄

Xe has 8 valence electrons and each O contributes 6 valence electrons. XeO₄ has 8+4×6 = 32 valence electrons. The central Xe atom has 4 bonding pairs (with O atoms) and 0 lone - pairs. The total number of electron domains around Xe is 4 (4 bonding + 0 non - bonding). According to VSEPR, the electron - domain geometry for 4 electron domains is tetrahedral.

Step4: Determine molecular geometry of XeO₄

With 4 bonding pairs and 0 lone - pairs around the central Xe atom, the molecular geometry is tetrahedral.

Answer:

Part 1 of 4
NBr₃
Electron Domain Geometry: tetrahedral
Molecular Geometry: trigonal pyramidal
Part 2 of 4
XeO₄
Electron Domain Geometry: tetrahedral
Molecular Geometry: tetrahedral