Question

value: 3
solve for x.
$3\sqrt{x + 1} + 4 = 25$
a. $x = 323$
b. $x = 48$
c. $x = 124$
d. $x = 5$

3/6

quiz 7.4.1 - solving radical equations
week 3 - assignment 8 of 13

Explanation:

Step1: Isolate the radical term

Subtract 4 from both sides:
$3\sqrt{x+1} = 25 - 4$
$3\sqrt{x+1} = 21$

Step2: Solve for the radical

Divide both sides by 3:
$\sqrt{x+1} = \frac{21}{3}$
$\sqrt{x+1} = 7$

Step3: Eliminate the square root

Square both sides of the equation:
$(\sqrt{x+1})^2 = 7^2$
$x + 1 = 49$

Step4: Solve for x

Subtract 1 from both sides:
$x = 49 - 1$
$x = 48$

Answer:

b. x=48