Question

if y varies inversely with x and y = 8 when x = 4, what is the value of y when x = 16? 64 2 32 4

Explanation:

Step1: Define inverse variation

$y = \frac{k}{x}$ where $k$ is constant.

Step2: Solve for constant $k$

Substitute $y=8$, $x=4$:
$8 = \frac{k}{4} \implies k = 8 \times 4 = 32$

Step3: Find $y$ at $x=16$

Use $k=32$, $x=16$:
$y = \frac{32}{16}$

Answer:

B. 2