Question

1. $delta abc$ has vertices $a(3,4), b(-5,2)$, and $c(1, - 4)$. determine an equation for

a) the median from c to ab
midpoint $d$ of $ab = (\frac{3+( - 5)}{2},\frac{4 + 2}{2})=(-1,3)$
slope $m_{cd}=\frac{3-( - 4)}{-1 - 1}=\frac{7}{-2}=-\frac{7}{2}$
$m =-\frac{7}{2}$
$y + 4=-\frac{7}{2}x-\frac{7}{2}$
$2y + 8=-7x - 7$
$7x+2y + 1=0$
b) the altitude from a to bc
$m_{bc}=\frac{-4 - 2}{1-( - 5)}=\frac{-6}{6}=-1$
slope of the altitude $m = 1$
$y - 4=1\times(x - 3)$
$y - 4=x - 3$
$y=x + 1$

Explanation:

Step1: Find mid - point of AB

The mid - point formula for two points $(x_1,y_1)$[LLM SSE On Failure]

Answer:

Step1: Find mid - point of AB

The mid - point formula for two points $(x_1,y_1)$[LLM SSE On Failure]