Question

a 1 g vial of acyclovir that has been reconstituted to a concentration of 50 mgt/ml has enough for 3 doses of 0.3 g each.
true
false
question 2 (2.5 points)
multidose vials of claforan 2 g are diluted with 10 ml of normal saline to yield 180 mg/ml. how many ml of the medication should be given if the patient is prescribed to receive 2000 mg of the medication?
9.6 ml
10.0 ml
11.1 ml
12.4 ml

Explanation:

Question 1

Step1: Convert concentration to g/mL

The concentration is \( 50 \, \text{mg/mL} \). Since \( 1 \, \text{g} = 1000 \, \text{mg} \), we convert \( 50 \, \text{mg} \) to grams: \( 50 \, \text{mg} = \frac{50}{1000} \, \text{g} = 0.05 \, \text{g/mL} \).

Step2: Find total volume of the vial

The vial has \( 1 \, \text{g} \) of acyclovir. Using the concentration \( C = \frac{m}{V} \) (where \( C \) is concentration, \( m \) is mass, \( V \) is volume), we solve for \( V \): \( V = \frac{m}{C} \). Substituting \( m = 1 \, \text{g} \) and \( C = 0.05 \, \text{g/mL} \), we get \( V = \frac{1}{0.05} = 20 \, \text{mL} \).

Step3: Calculate total mass of 3 doses

Each dose is \( 0.3 \, \text{g} \), so 3 doses have a total mass of \( 3 \times 0.3 \, \text{g} = 0.9 \, \text{g} \).

Step4: Check if total mass is less than vial's mass

The vial has \( 1 \, \text{g} \), and the total mass of 3 doses is \( 0.9 \, \text{g} \), which is less than \( 1 \, \text{g} \). So there is enough for 3 doses.

Step1: Recall the formula for volume from concentration

The formula relating mass (\( m \)), concentration (\( C \)), and volume (\( V \)) is \( V = \frac{m}{C} \), where \( C \) is in \( \text{mg/mL} \), \( m \) is in \( \text{mg} \), and \( V \) is in \( \text{mL} \).

Step2: Substitute the given values

We are given \( m = 2000 \, \text{mg} \) and \( C = 180 \, \text{mg/mL} \). Plugging these into the formula: \( V = \frac{2000}{180} \approx 11.1 \, \text{mL} \).

Answer:

True

Question 2