Question

1. if the voltage across a resistor is 12 v and the current is 2 a, what is the resistance?○ 6 ω○ 24 ω○ 5 ω○ 10 ω2. a series circuit has a 9 v battery and three resistors of 1 ω each. what is the current in the circuit?○ 1 a○ 3 a○ 2 a○ 4 a3. a 12 v battery is connected to a 4 ω resistor. what is the power dissipated by the resistor?○ 36 w○ 12 w○ 16 w○ 20 w4. a series circuit has a total resistance of 15 ω and a current of 2 a. what is the voltage supplied?○ 7.5 v○ 30 v○ 17 v○ 13 v

Explanation:

Step1: Apply Ohm's Law (V=IR)

$R = \frac{V}{I} = \frac{12}{2} = 6\ \Omega$

Step2: Find total series resistance

$R_{total} = 1+1+1 = 3\ \Omega$

Step3: Calculate circuit current

$I = \frac{V}{R_{total}} = \frac{9}{3} = 3\ A$

Step4: Use power formula $P=\frac{V^2}{R}$

$P = \frac{12^2}{4} = \frac{144}{4} = 36\ W$

Step5: Apply Ohm's Law for voltage

$V = I \times R_{total} = 2 \times 15 = 30\ V$

Answer:

1. 6 Ω
2. 3 A
3. 36 W
4. 30 V