Question

water tower: find the hydrostatic pressure at the base of a 25 - meter - high water tower filled with water. (water density = 1000 kg/m³) p = pa
question 5 1 pts
swimming pool: calculate the pressure 2 meters below the surface in a swimming pool. (water density = 1000 kg/m³) p = pa

Explanation:

Step1: Recall hydrostatic - pressure formula

$p =
ho gh$, where $
ho$ is density, $g$ is acceleration due to gravity ($g = 9.8\ m/s^{2}$), and $h$ is depth.

Step2: Solve for water - tower pressure

For the water - tower, $
ho = 1000\ kg/m^{3}$, $g = 9.8\ m/s^{2}$, $h = 25\ m$.
$p_1=
ho gh=1000\times9.8\times25 = 245000\ Pa$

Step3: Solve for swimming - pool pressure

For the swimming - pool, $
ho = 1000\ kg/m^{3}$, $g = 9.8\ m/s^{2}$, $h = 2\ m$.
$p_2=
ho gh=1000\times9.8\times2=19600\ Pa$

Answer:

For water - tower: $245000\ Pa$
For swimming - pool: $19600\ Pa$