Question

1. we will first find the number of moles of base (naoh) used to neutralize the unknown acid by using the molarity equation: molarity = $\frac{moles of base}{volume of base used (l)}$

Explanation:

Step1: Rearrange the molarity formula

To find the moles of base, we rearrange the formula $Molarity=\frac{Moles\ of\ base}{Volume\ of\ base\ used (L)}$ to $Moles\ of\ base = Molarity\times Volume\ of\ base\ used (L)$.

Step2: Substitute known values

If we know the molarity of $NaOH$ and the volume of $NaOH$ used (in liters), we substitute these values into the rearranged formula to calculate the moles of $NaOH$.

Answer:

The moles of base ($NaOH$) can be found using the formula $Moles\ of\ base = Molarity\times Volume\ of\ base\ used (L)$ after substituting the known values of molarity and volume of the base used.