Question

we have b terms on both sides of the equation, and we want to get the b terms on one side. we can subtract \\(\frac{2}{3}b\\) on the left side of the equation so that there are no b terms on the left. then we need to subtract \\(\frac{2}{3}b\\) from the right to keep the equation balanced. go for it.
\\(\frac{2}{3}b + 9\\) \\(=\\) \\(b + 11\\)
\\(-\frac{2}{3}b\\) \\(\quad -\frac{2}{3}b\\)
\\(\square\\) \\(=\\) \\(\square\\)

Explanation:

Step1: Simplify left side

$\frac{2}{3}b + 9 - \frac{2}{3}b = 9$

Step2: Simplify right side

$b + 11 - \frac{2}{3}b = \frac{1}{3}b + 11$

Answer:

Top box: $9$
Bottom box: $\frac{1}{3}b + 11$