Question

we have $b$ terms on both sides of the equation, and we want to get the $b$ terms on one side. we can subtract $\frac{2}{3}b$ on the left side of the equation so that there are no $b$ terms on the left. then we need to subtract $\frac{2}{3}b$ from the right to keep the equation balanced. go for it.$\frac{2}{3}b + 5 = b + 9LXB0square = square$

Explanation:

Step1: Simplify left side

$\frac{2}{3}b + 5 - \frac{2}{3}b = 5$

Step2: Simplify right side

$b + 9 - \frac{2}{3}b = \frac{3}{3}b - \frac{2}{3}b + 9 = \frac{1}{3}b + 9$

Answer:

Left box: $5$
Right box: $\frac{1}{3}b + 9$