Question

what is the acceleration of a ball that is dropped off the side of a cliff after 1,2,3,4,5 seconds? (assume g is rounded to -10 m/s²)
-10,-10,-10,-10,-10 m/s²
-10, -20, -30, -40, -50 m/s²
-5,-10,-15, -20, -25 m/s²

Explanation:

Step1: Recall free - fall concept

In free - fall near the Earth's surface, the acceleration due to gravity is constant for an object in the absence of air resistance.

Step2: Identify acceleration value

The acceleration due to gravity $g$ is approximately $- 10\ m/s^{2}$ (negative because it acts downwards), and it does not depend on the time of fall. So after 1, 2, 3, 4, 5 seconds, the acceleration of the ball is always $-10\ m/s^{2}$.

Answer:

-10, -10, -10, -10, -10 m/s²