Question

1. what is always written first in the name of an acid to identify it as a binary acid?

using the following list of ions that are not on your ion table, …

1. correctly name the following oxyacids:

a. $\ce{h2po2}$
b. $\ce{h2teo4}$
c. $\ce{h2seo3}$
d. $\ce{h2co2}$
e. $\ce{hbro2}$

1. construct the chemical formula for the following oxyacids:

a. fluorous acid
b. benzoic acid
c. fulminic acid
d. phthalic acid
e. hypobromous acid
ions that are not on the ion table handout:
formate $\ce{cho2^{1-}}$
benzoate $\ce{c7h5o2^{1-}}$
bromite $\ce{bro2^{1-}}$
carbonite $\ce{co2^{2-}}$
iodite $\ce{io2^{1-}}$
phthalate $\ce{c8h4o4^{2-}}$
fluorate $\ce{fo3^{1-}}$
fluorite $\ce{fo2^{1-}}$
selenate $\ce{seo4^{2-}}$
selenite $\ce{seo3^{2-}}$
borate $\ce{bo3^{3-}}$
fulminate $\ce{cno^{1-}}$
perbromate $\ce{bro4^{1-}}$
perrhenate $\ce{reo4^{1-}}$
isocyanate $\ce{nco^{1-}}$
hypobromite $\ce{bro^{1-}}$
hypoiodite $\ce{io^{1-}}$
hypophosphite $\ce{po2^{2-}}$
tellurate $\ce{teo4^{2-}}$
tellurite $\ce{teo3^{2-}}$
provided in front of the number.

Explanation:

Step1: Identify anion for 4a

$\ce{H2PO2}$ corresponds to hypophosphite $\ce{PO2^{2-}}$, so name is hypophosphorous acid.

Step2: Identify anion for 4b

$\ce{H2TeO4}$ corresponds to tellurate $\ce{TeO4^{2-}}$, so name is telluric acid.

Step3: Identify anion for 4c

$\ce{H2SeO3}$ corresponds to selenite $\ce{SeO3^{2-}}$, so name is selenous acid.

Step4: Identify anion for 4d

$\ce{H2CO2}$ corresponds to formate $\ce{CHO2^-}$, so name is formic acid.

Step5: Identify anion for 4e

$\ce{HBrO2}$ corresponds to bromite $\ce{BrO2^-}$, so name is bromous acid.

Step6: Match acid to anion for 5a

Fluorous acid comes from fluorite $\ce{FO2^-}$, balance charge: $\ce{HFO2}$.

Step7: Match acid to anion for 5b

Benzoic acid comes from benzoate $\ce{C7H5O2^-}$, balance charge: $\ce{HC7H5O2}$.

Step8: Match acid to anion for 5c

Fulminic acid comes from fulminate $\ce{CNO^-}$, balance charge: $\ce{HCNO}$.

Step9: Match acid to anion for 5d

Phthalic acid comes from phthalate $\ce{C8H4O4^{2-}}$, balance charge: $\ce{H2C8H4O4}$.

Step10: Match acid to anion for 5e

Hypobromous acid comes from hypobromite $\ce{BrO^-}$, balance charge: $\ce{HBrO}$.

Answer:

Question 4:

a. hypophosphorous acid
b. telluric acid
c. selenous acid
d. formic acid
e. bromous acid

Question 5:

a. $\ce{HFO2}$
b. $\ce{HC7H5O2}$
c. $\ce{HCNO}$
d. $\ce{H2C8H4O4}$
e. $\ce{HBrO}$