Question

what is the area of the arrow shown? 2 in. 16 in. 6 in. 20 in. 52 in.² 56 in.² 80 in.² 44 in.²

Explanation:

Step1: Calculate rectangle area

The rectangle has length $l = 16$ in and width $w = 2$ in. The area of a rectangle $A_{r}=l\times w$. So $A_{r}=16\times2 = 32$ in.$^{2}$.

Step2: Calculate triangle area

The base of the triangle $b=6 - 2=4$ in and the height $h = 20 - 16 = 4$ in. The area of a triangle $A_{t}=\frac{1}{2}\times b\times h$. So $A_{t}=\frac{1}{2}\times4\times4=8$ in.$^{2}$.

Step3: Calculate total area

The arrow is composed of the rectangle and two congruent triangles. Total area $A = A_{r}+ 2A_{t}=32+2\times10=52$ in.$^{2}$.

Answer:

52 in.$^{2}$