Question

what is the area of triangle abc? round to the nearest tenth of a square unit. trigonometric area formula: area = $\frac{1}{2}absin c$ 54.9 square units 58.8 square units 61.8 square units 64.1 square units

Explanation:

Step1: Identify sides and included angle

a=10, b=13, θ=72°

Step2: Calculate sin(72°)

sin(72°)≈0.9511

Step3: Apply area formula

Area=$\frac{1}{2}ab\sinθ=\frac{1}{2}×10×13×0.9511≈61.8$

Answer:

C. 61.8 square units